原文:
给定两个数 x 和 y，用递归求积。 例:
input : x = 5, y = 2
output : 10
input : x = 100, y = 5
output : 500
方法 1)如果 x 小于 y，交换两个变量值 2)递归求 y 乘以 x 的和 3)如果其中任何一个变为零，返回 0
c
// c program to find product
// of 2 numbers using recursion
#include
using namespace std;
// recursive function to calculate
// multiplication of two numbers
int product(int x, int y)
{
// if x is less than
// y swap the numbers
if (x < y)
return product(y, x);
// iteratively calculate
// y times sum of x
else if (y != 0)
return (x product(x, y - 1));
// if any of the two numbers is
// zero return zero
else
return 0;
}
// driver code
int main()
{
int x = 5, y = 2;
cout << product(x, y);
return 0;
}
java 语言(一种计算机语言，尤用于创建网站)
// java program to find product
// of 2 numbers using recursion
import java.io.*;
import java.util.*;
class gfg
{
// recursive function to calculate
// multiplication of two numbers
static int product(int x, int y)
{
// if x is less than
// y swap the numbers
if (x < y)
return product(y, x);
// iteratively calculate
// y times sum of x
else if (y != 0)
return (x product(x, y - 1));
// if any of the two numbers is
// zero return zero
else
return 0;
}
// driver code
public static void main (string[] args)
{
int x = 5, y = 2;
system.out.println(product(x, y));
}
}
// this code is contributed by gitanjali.
python 3
# python3 to find product of
# 2 numbers using recursion
# recursive function to calculate
# multiplication of two numbers
def product( x , y ):
# if x is less than y swap
# the numbers
if x < y:
return product(y, x)
# iteratively calculate y
# times sum of x
elif y != 0:
return (x product(x, y - 1))
# if any of the two numbers is
# zero return zero
else:
return 0
# driver code
x = 5
y = 2
print( product(x, y))
# this code is contributed
# by abhishek sharma44.
c
// c# program to find product
// of 2 numbers using recursion
using system;
class gfg
{
// recursive function to calculate
// multiplication of two numbers
static int product(int x, int y)
{
// if x is less than
// y swap the numbers
if (x < y)
return product(y, x);
// iteratively calculate
// y times sum of x
else if (y != 0)
return (x product(x, y - 1));
// if any of the two numbers is
// zero return zero
else
return 0;
}
// driver code
public static void main ()
{
int x = 5, y = 2;
console.writeline(product(x, y));
}
}
// this code is contributed by vt_m.
服务器端编程语言（professional hypertext preprocessor 的缩写）
java 描述语言
输出:
10
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