原文:
给定一个字符串，在矩阵中打印出来，这样就形成了一个加号。
示例:
input: top
output:
x t x
t o p
x p x
input: fever
output:
x x f x x
x x e x x
f e v e r
x x e x x
x x r x x
进场: 思路很简单。首先，我们可以访问矩阵的每个元素，并使其为“x”。然后我们将在矩阵的中间行和中间列插入字符串的字符。例如，我们有一个长度为 5 的字符串。所以我们需要一个(5x5)矩阵。
为了访问矩阵的中间列，列索引被设为常数，并等于(n/2)，其中 n 是字符串的长度。它的行索引将从 0 变为(n-1)。 要访问中间行，行索引将被设为常量并等于(n/2)，列索引将从 0 变为(n-1)。
下面是上述方法的实现:
c
// cpp program to print the
// string in 'plus' pattern
#include
#define max 100
using namespace std;
// function to make a cross in the matrix
void carvecross(string str)
{
int n = str.length();
if (n % 2 == 0)
{
/* as, it is not possible to make
the cross exactly in the middle of
the matrix with an even length string.*/
cout << "not possible. please enter "
<< "odd length string.\n";
}
else {
// declaring a 2d array i.e a matrix
char arr[max][max];
int m = n / 2;
/* now, we will fill all the
elements of the array with 'x'*/
for (int i = 0; i < n; i ) {
for (int j = 0; j < n; j ) {
arr[i][j] = 'x';
}
}
/* now, we will place the characters
of the string in the matrix, such
that a cross is formed in it.*/
for (int i = 0; i < n; i )
{
/* here the characters of the
string will be added in the
middle column of our array.*/
arr[i][m] = str[i];
}
for (int i = 0; i < n; i )
{
// here the characters of the
// string will be added in the
// middle row of our array.
arr[m][i] = str[i];
}
/* now finally, we will print
the array*/
for (int i = 0; i < n; i ) {
for (int j = 0; j < n; j ) {
cout << arr[i][j] << " ";
}
cout << "\n";
}
}
}
// driver code
int main()
{
string str = "picture";
carvecross(str);
return 0;
}
java 语言(一种计算机语言，尤用于创建网站)
// java program to print the
// string in 'plus' pattern
class gfg {
static final int max = 100;
// function to make a cross in the matrix
static void carvecross(string str) {
int n = str.length();
if (n % 2 == 0) {
// as, it is not possible to make
// the cross exactly in the middle of
// the matrix with an even length string.
system.out.print("not possible. please enter "
"odd length string.\n");
}
else {
// declaring a 2d array i.e a matrix
char arr[][] = new char[max][max];
int m = n / 2;
// now, we will fill all the
// elements of the array with 'x'
for (int i = 0; i < n; i )
{
for (int j = 0; j < n; j )
{
arr[i][j] = 'x';
}
}
// now, we will place the characters
// of the string in the matrix, such
// that a cross is formed in it.
for (int i = 0; i < n; i ) {
// here the characters of the
// string will be added in the
// middle column of our array.
arr[i][m] = str.charat(i);
}
for (int i = 0; i < n; i ) {
// here the characters of the
// string will be added in the
// middle row of our array.
arr[m][i] = str.charat(i);
}
// now finally, we will print
// the array
for (int i = 0; i < n; i )
{
for (int j = 0; j < n; j )
{
system.out.print(arr[i][j] " ");
}
system.out.print("\n");
}
}
}
// driver code
public static void main(string[] args) {
string str = "picture";
carvecross(str);
}
}
// this code is contributed by anant agarwal.
python 3
# python 3 program to print the
# string in 'plus' pattern
max = 100
# function to make a cross
# in the matrix
def carvecross(str):
n = len(str)
if (n % 2 == 0) :
''' as, it is not possible to make
the cross exactly in the middle of
the matrix with an even length string.'''
print("not possible. please enter "
, "odd length string.\n")
else :
# declaring a 2d array i.e a matrix
arr = [[ false for x in range(max)]
for y in range(max)]
m = n // 2
''' now, we will fill all the
elements of the array with 'x'''
for i in range( n) :
for j in range(n) :
arr[i][j] = 'x'
'''now, we will place the characters
of the string in the matrix, such
that a cross is formed in it.'''
for i in range(n):
''' here the characters of the
string will be added in the
middle column of our array.'''
arr[i][m] = str[i]
for i in range(n):
# here the characters of the
# string will be added in the
# middle row of our array.
arr[m][i] = str[i]
# now finally, we will print
# the array
for i in range(n):
for j in range(n):
print( arr[i][j] , end=" ")
print()
# driver code
if __name__ == "__main__":
str = "picture"
carvecross(str)
# this code is contributed
# by chitranayal
c
// c# program to print the
// string in 'plus' pattern
using system;
class gfg {
static int max = 100;
// function to make a cross in the matrix
static void carvecross(string str) {
int n = str.length;
if (n % 2 == 0) {
// as, it is not possible to make
// the cross exactly in the middle of
// the matrix with an even length string.
console.write("not possible. please enter "
"odd length string.");
}
else {
// declaring a 2d array i.e a matrix
char [,]arr = new char[max,max];
int m = n / 2;
// now, we will fill all the
// elements of the array with 'x'
for (int i = 0; i < n; i )
{
for (int j = 0; j < n; j )
{
arr[i,j] = 'x';
}
}
// now, we will place the characters
// of the string in the matrix, such
// that a cross is formed in it.
for (int i = 0; i < n; i ) {
// here the characters of the
// string will be added in the
// middle column of our array.
arr[i,m] = str[i];
}
for (int i = 0; i < n; i ) {
// here the characters of the
// string will be added in the
// middle row of our array.
arr[m,i] = str[i];
}
// now finally, we will print
// the array
for (int i = 0; i < n; i )
{
for (int j = 0; j < n; j )
{
console.write(arr[i,j] " ");
}
console.writeline();
}
}
}
// driver code
public static void main() {
string str = "picture";
carvecross(str);
}
}
// this code is contributed by vt_m.
服务器端编程语言（professional hypertext preprocessor 的缩写）
output:
x x x p x x x
x x x i x x x
x x x c x x x
p i c t u r e
x x x u x x x
x x x r x x x
x x x e x x x
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