原文:
给定一个由大写字母和小写字母组成的字符串，任务是打印字符串，并替换掉任何字符(包括空格，并认为大写和小写相同)。 例:
input : it is a long day dear.
output : it sa longdy ear.
print first i and then ignore next i.
similarly print first space then
ignore next space.
input : geeks for geeks
output : geks fore
问于:t2】
由于我们必须以另一种方式打印字符，因此开始遍历字符串并执行以下两个步骤:-
- 增加哈希表中当前字符的出现次数。
- 检查计数是否为奇数，然后打印当前字符，否则不打印。
c
// c program to print the string in given pattern
#include
using namespace std;
// function to print the string
void printstringalternate(string str)
{
unordered_map occ;
// start traversing the string
for (int i = 0; i < str.length(); i ) {
// convert uppercase to lowercase
char temp = tolower(str[i]);
// increment occurrence count
occ[temp] ;
// if count is odd then print the character
if (occ[temp] & 1)
cout << str[i];
}
cout << endl;
}
// drivers code
int main()
{
string str = "geeks for geeks";
string str2 = "it is a long day dear";
printstringalternate(str);
printstringalternate(str2);
return 0;
}
java 语言(一种计算机语言，尤用于创建网站)
// java program to print the string in given pattern
import java.io.*;
class gfg
{
// function to print the string
static void printstringalternate(string str)
{
int[] occ = new int[122];
// convert uppercase to lowercase
string s = str.tolowercase();
// start traversing the string
for (int i = 0; i < str.length(); i )
{
char temp = s.charat(i);
// increment occurrence count
occ[temp] ;
// if count is odd then print the character
if (occ[temp]%2 != 0)
system.out.print(str.charat(i));
}
system.out.println();
}
// driver program
public static void main (string[] args)
{
string str1 = "geeks for geeks";
string str2 = "it is a long day dear";
printstringalternate(str1);
printstringalternate(str2);
}
}
// contributed by pramod kumar
python 3
# python3 program to print the string
# in given pattern
# function to print the string
def printstringalternate(string):
occ = {}
# start traversing the string
for i in range(0, len(string)):
# convert uppercase to lowercase
temp = string[i].lower()
# increment occurrence count
occ[temp] = occ.get(temp, 0) 1
# if count is odd then print the character
if occ[temp] & 1:
print(string[i], end = "")
print()
# driver code
if __name__ == "__main__":
string = "geeks for geeks"
string2 = "it is a long day dear"
printstringalternate(string)
printstringalternate(string2)
# this code is contributed by rituraj jain
c
// c# program to print the
// string in given pattern
using system;
public class gfg {
// function to print the string
static void printstringalternate(string str)
{
int[] occ = new int[122];
// convert uppercase to lowercase
string s = str.tolower();
// start traversing the string
for (int i = 0; i < str.length; i )
{
char temp = s[i];
// increment occurrence count
occ[temp] ;
// if count is odd then print
// the character
if (occ[temp] % 2 != 0)
console.write(str[i]);
}
console.writeline();
}
// driver code
public static void main ()
{
string str1 = "geeks for geeks";
string str2 = "it is a long day dear";
printstringalternate(str1);
printstringalternate(str2);
}
}
// this code is contributed by sam007.
服务器端编程语言（professional hypertext preprocessor 的缩写）
java 描述语言
输出:
geks fore
it sa longdy ear
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