原文:

给定 3 正整数 c1，c2 和 n，其中 n 是任务是打印填充有矩形图案的矩阵，该矩形图案具有中心坐标 c1、c2 ，使得 0 < = c1、c2 < n.

示例:

输入 : c1 = 2，c2 = 2，n = 5 输出: 2 2 2 2 2 2 2 2 1 1 2 2 1 0 1 2 2 1 1 2 2 2 2 2 2 2 2 2 2

输入: c1 = 3，c2 = 4，n = 7 t3】输出:t5】4 3 3 3 3 3 3 3 3 4 3 2 2 2 2 4 3 2 1 1 1 2 4 3 2 1 0 1 2 4 3 2 1 1 2 4 3 2 2 2 2 2 2 4 3 3 3 3 3 3 3 3 3

方法:这个问题可以通过使用两个嵌套循环来解决。按照以下步骤解决此问题:

  • 使用变量 i 在[0，n-1]范围内迭代，并执行以下步骤:
    • 使用变量 j 在[0，n-1]范围内迭代，并执行以下步骤:
      • 打印 abs(c1–i)和 abs(c2–j)的最大值。
    • 打印新行。

下面是上述方法的实现:

c 

// c   program for the above approach
#include 
using namespace std;
// function to print the matrix filled
// with rectangle pattern having center
// coordinates are c1, c2
void printrectpattern(int c1, int c2, int n)
{
    // iterate in the range[0, n-1]
    for (int i = 0; i < n; i  ) {
        // iterate in the range[0, n-1]
        for (int j = 0; j < n; j  ) {
            cout << (max(abs(c1 - i), abs(c2 - j))) << " ";
        }
        cout << endl;
    }
}
// driver code
int main()
{
    // given input
    int c1 = 2;
    int c2 = 2;
    int n = 5;
    // function call
    printrectpattern(c1, c2, n);
    // this code is contributed by potta lokesh
    return 0;
}

java 语言(一种计算机语言，尤用于创建网站)

// java program for the above approach
import java.io.*;
class gfg{
// function to print the matrix filled
// with rectangle pattern having center
// coordinates are c1, c2
static void printrectpattern(int c1, int c2, int n)
{
    // iterate in the range[0, n-1]
    for(int i = 0; i < n; i  )
    {
        // iterate in the range[0, n-1]
        for(int j = 0; j < n; j  )
        {
            system.out.print((math.max(math.abs(c1 - i),
                              math.abs(c2 - j)))   " ");
        }
        system.out.println();
    }
}
// driver code
public static void main(string[] args)
{
    // given input
    int c1 = 2;
    int c2 = 2;
    int n = 5;
    // function call
    printrectpattern(c1, c2, n);
}
}
// this code is contributed by sanjoy_62

python 3

# python3 program for the above approach
# function to print the matrix filled
# with rectangle pattern having center
# coordinates are c1, c2
def printrectpattern(c1, c2, n):
    # iterate in the range[0, n-1]
    for i in range(n):
        # iterate in the range[0, n-1]
        for j in range(n):
            print(max(abs(c1 - i), abs(c2 - j)), end = " ")
        print("")
# driver code
# given input
c1 = 2
c2 = 2
n = 5
# function call
printrectpattern(c1, c2, n)

c

// c# program for the above approach
using system;
class gfg{
// function to print the matrix filled
// with rectangle pattern having center
// coordinates are c1, c2
static void printrectpattern(int c1, int c2, int n)
{
    // iterate in the range[0, n-1]
    for(int i = 0; i < n; i  )
    {
        // iterate in the range[0, n-1]
        for(int j = 0; j < n; j  )
        {
            console.write((math.max(math.abs(c1 - i),
                           math.abs(c2 - j)))   " ");
        }
        console.writeline();
    }
}
// driver code
public static void main(string[] args)
{
    // given input
    int c1 = 2;
    int c2 = 2;
    int n = 5;
    // function call
    printrectpattern(c1, c2, n);
}
}
// this code is contributed by target_2

java 描述语言

output: 

2 2 2 2 2 
2 1 1 1 2 
2 1 0 1 2 
2 1 1 1 2 
2 2 2 2 2

时间复杂度: o(n ^2) 辅助空间: o(1)

麻将胡了pg电子网站的版权属于：月萌api www.moonapi.com，转载请注明出处

本文链接：http://www.moonapi.com/news/38672.html