原文:
给定一个整数 n，任务是找到一个长度为(n 1)的字符串(仅考虑小写字符)，使得任意位置的字符在字典上应大于其紧接的下一个字符。 例:
input: 2
output: cba
c is greater than b and
b is greater than a
input: 5
output: fedcba
进场:
- 以相反的顺序声明一个包含所有字母的字符串。
- 用 26 取给定数的模。因此，如果该值小于 26，运行从26 –(模数值 1) 到 25 的循环，转到字符串的索引并打印该索引。
- 如果模数值大于 0，则用 26 除模数值，然后循环到 0 到 25，并根据给定的计算值打印字符串的每个元素。
以下是上述方法的实现:
c
// c program to print a string in reverse
// alphabetical order upto given number
#include
using namespace std;
// function that prints the required string
string printstring(int n, string str)
{
string str2 = "";
// find modulus with 26
int extrachar = n % 26;
// print extra characters required
if (extrachar >= 1) {
for (int i = 26 - (extrachar 1); i <= 25; i )
str2 = str[i];
}
int countofstr = n / 26;
// print the given reverse string countofstr times
for (int i = 1; i <= countofstr; i ) {
for (int j = 0; j < 26; j )
str2 = str[j];
}
return str2;
}
// driver code
int main()
{
int n = 30;
// initialize a string in reverse order
string str = "zyxwvutsrqponmlkjihgfedcba";
cout << printstring(n, str);
return 0;
}
java 语言(一种计算机语言，尤用于创建网站)
// java program to print a string in reverse
// alphabetical order upto given number
class gfg {
// function that prints the required string
static string printstring(int n, string str) {
string str2 = "";
// find modulus with 26
int extrachar = n % 26;
// print extra characters required
if (extrachar >= 1) {
for (int i = 26 - (extrachar 1); i <= 25; i ) {
str2 = str.charat(i);
}
}
int countofstr = n / 26;
// print the given reverse string countofstr times
for (int i = 1; i <= countofstr; i ) {
for (int j = 0; j < 26; j ) {
str2 = str.charat(j);
}
}
return str2;
}
// driver code
public static void main(string[] args) {
int n = 30;
// initialize a string in reverse order
string str = "zyxwvutsrqponmlkjihgfedcba";
system.out.println(printstring(n, str));
}
}
// this code is contributed by rajput-ji
python 3
# python 3 program to print a
# string in reverse alphabetical
# order upto given number
# function that prints the
# required string
def printstring(n, str):
str2 = ""
# find modulus with 26
extrachar = n % 26
# print extra characters required
if (extrachar >= 1) :
for i in range( 26 - (extrachar 1), 26):
str2 = str[i]
countofstr = n // 26
# print the given reverse
# string countofstr times
for i in range(1, countofstr 1) :
for j in range(26):
str2 = str[j]
return str2
# driver code
if __name__ == "__main__":
n = 30
# initialize a string in
# reverse order
str = "zyxwvutsrqponmlkjihgfedcba"
print(printstring(n, str))
# this code is contributed
# by chitranayal
c
// c# program to print a string in reverse
// alphabetical order upto given number
using system;
public class gfg {
// function that prints the required string
static string printstring(int n, string str) {
string str2 = "";
// find modulus with 26
int extrachar = n % 26;
// print extra characters required
if (extrachar >= 1) {
for (int i = 26 - (extrachar 1); i <= 25; i ) {
str2 = str[i];
}
}
int countofstr = n / 26;
// print the given reverse string countofstr times
for (int i = 1; i <= countofstr; i ) {
for (int j = 0; j < 26; j ) {
str2 = str[j];
}
}
return str2;
}
// driver code
public static void main() {
int n = 30;
// initialize a string in reverse order
string str = "zyxwvutsrqponmlkjihgfedcba";
console.write(printstring(n, str));
}
}
// this code is contributed by rajput-ji
java 描述语言
输出:
edcbazyxwvutsrqponmlkjihgfedcba
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